• Welcome to ZD Forums! You must create an account and log in to see and participate in the Shoutbox chat on this main index page.

Count to 100 Before a Mod Posts

Big Octo

=^)
Joined
Jul 2, 2011
Location
The
15.
yes.gif
 

Kybyrian

Joined
Jan 31, 2008
Location
Amherst, MA
Gender
Didn't I already answer this one?
If given a diagram of two pairs of vertical angles, where one vertical angle on the bottom is narrow and can be defined as 3x, and the wider angle on the right is 5x - 13, and the wider angle on the left is 8y + 6, you can solve for x and y in the following manner:

We can prove that the narrow angle on top is 3x, since two vertical angles always equal each other. We also know that the two angles on either side of the diagram are linear pairs (draw a diagram if you wish). This means that they add up to 180 degrees. We can form this equation: 3x + 5x - 13 = 180.

Combine like terms.

8x - 13 = 180

Add 13 to both sides.

8x = 193

Divide both sides by 8.

x = 24.125 (or 24 and 1/8)

Now we just need to solve for y. We can do this with the following equation:

8y + 6 + 3x = 180

We can form this equation because we know the two linear pairs add to 180 degrees. Now we need to eliminate a variable. Plug the previously solved x value into the equation.

8y + 6 + 3(24.125) = 180

8y + 6 + 72.375 = 180

Combine like terms.

8y + 78.375 = 180

Subtract 78.375 from both sides.

8y = 101.625

Divide both sides by 8.

y = 12.703125
 

Users who are viewing this thread

Top Bottom